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Answer :
To solve the subtraction problem
[tex]$$313 - 225,$$[/tex]
we can perform the subtraction column by column.
1. Subtracting the Ones Place:
In [tex]$313$[/tex], the ones digit is [tex]$3$[/tex], and in [tex]$225$[/tex], the ones digit is [tex]$5$[/tex]. Since [tex]$3$[/tex] is less than [tex]$5$[/tex], we need to borrow [tex]$1$[/tex] from the tens place. Borrowing [tex]$1$[/tex] is equivalent to adding [tex]$10$[/tex] to the ones digit. Now, the ones digit becomes:
[tex]$$3 + 10 = 13.$$[/tex]
Now, subtract the ones:
[tex]$$13 - 5 = 8.$$[/tex]
2. Subtracting the Tens Place:
After borrowing, the tens digit in [tex]$313$[/tex] (which was originally [tex]$1$[/tex]) is reduced by [tex]$1$[/tex], so it becomes [tex]$0$[/tex]. The tens digit in [tex]$225$[/tex] is [tex]$2$[/tex]. Since [tex]$0$[/tex] is less than [tex]$2$[/tex], we again need to borrow [tex]$1$[/tex] from the hundreds place. Borrowing [tex]$1$[/tex] adds [tex]$10$[/tex] to the tens digit. Now, the tens digit becomes:
[tex]$$0 + 10 = 10.$$[/tex]
Now, subtract the tens:
[tex]$$10 - 2 = 8.$$[/tex]
3. Subtracting the Hundreds Place:
After borrowing, the hundreds digit in [tex]$313$[/tex] (which was originally [tex]$3$[/tex]) is reduced by [tex]$1$[/tex], so it becomes [tex]$2$[/tex]. The hundreds digit in [tex]$225$[/tex] is [tex]$2$[/tex]. Now subtract:
[tex]$$2 - 2 = 0.$$[/tex]
4. Combining the Results:
Placing the results of each subtraction in their respective places, we have:
- Hundreds: [tex]$0$[/tex]
- Tens: [tex]$8$[/tex]
- Ones: [tex]$8$[/tex]
Thus, the final answer is:
[tex]$$\boxed{88}.$$[/tex]
[tex]$$313 - 225,$$[/tex]
we can perform the subtraction column by column.
1. Subtracting the Ones Place:
In [tex]$313$[/tex], the ones digit is [tex]$3$[/tex], and in [tex]$225$[/tex], the ones digit is [tex]$5$[/tex]. Since [tex]$3$[/tex] is less than [tex]$5$[/tex], we need to borrow [tex]$1$[/tex] from the tens place. Borrowing [tex]$1$[/tex] is equivalent to adding [tex]$10$[/tex] to the ones digit. Now, the ones digit becomes:
[tex]$$3 + 10 = 13.$$[/tex]
Now, subtract the ones:
[tex]$$13 - 5 = 8.$$[/tex]
2. Subtracting the Tens Place:
After borrowing, the tens digit in [tex]$313$[/tex] (which was originally [tex]$1$[/tex]) is reduced by [tex]$1$[/tex], so it becomes [tex]$0$[/tex]. The tens digit in [tex]$225$[/tex] is [tex]$2$[/tex]. Since [tex]$0$[/tex] is less than [tex]$2$[/tex], we again need to borrow [tex]$1$[/tex] from the hundreds place. Borrowing [tex]$1$[/tex] adds [tex]$10$[/tex] to the tens digit. Now, the tens digit becomes:
[tex]$$0 + 10 = 10.$$[/tex]
Now, subtract the tens:
[tex]$$10 - 2 = 8.$$[/tex]
3. Subtracting the Hundreds Place:
After borrowing, the hundreds digit in [tex]$313$[/tex] (which was originally [tex]$3$[/tex]) is reduced by [tex]$1$[/tex], so it becomes [tex]$2$[/tex]. The hundreds digit in [tex]$225$[/tex] is [tex]$2$[/tex]. Now subtract:
[tex]$$2 - 2 = 0.$$[/tex]
4. Combining the Results:
Placing the results of each subtraction in their respective places, we have:
- Hundreds: [tex]$0$[/tex]
- Tens: [tex]$8$[/tex]
- Ones: [tex]$8$[/tex]
Thus, the final answer is:
[tex]$$\boxed{88}.$$[/tex]
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Rewritten by : Brahmana