Welcome to the article A student performed the heat of fusion lab and measured the heat of fusion to be 313 J g Calculate the student s percent error. On this page, you will learn the essential and logical steps to better understand the topic being discussed. We hope the information provided helps you gain valuable insights and is easy to follow. Let’s begin the discussion!
Answer :
Final answer:
The percent error can be calculated by using the formula: Percent Error = (|Measured Value - Accepted Value| / Accepted Value) x 100. In this case, the percent error is 6.29%.
Explanation:
The percent error can be calculated by using the formula:
Percent Error = (|Measured Value - Accepted Value| / Accepted Value) x 100
Given that the student measured the heat of fusion to be 313 J/g, the accepted value is 334 J/g (as mentioned in the definition provided). Let's calculate the percent error:
Percent Error = (|313 - 334| / 334) x 100 = 6.29%
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Rewritten by : Brahmana
A student has performed the heat of fusion lab and measured the heat of fusion to be 313 J/g. In order to calculate the percent error, we need to know the experimental value and the true value of the heat of fusion.
The formula to calculate the percent error is as follows: Percent error = (experimental value - true value) / true value * 100%To calculate the percent error for the student who performed the heat of fusion lab and measured the heat of fusion to be 313 J/g, we need to know the true value of the heat of fusion. The true value of the heat of fusion of a substance is the amount of energy required to melt one gram of that substance without changing its temperature. This value can be found in a reference book or online database.
For example, the true value of the heat of fusion of water is 333.55 J/g at 0°C. Therefore, we can calculate the percent error as follows: Percent error = (313 J/g - 333.55 J/g) / 333.55 J/g * 100% = -6.17%The negative sign indicates that the student's measurement is lower than the true value. The percent error of -6.17% means that the student's measurement is 6.17% lower than the true value of the heat of fusion.
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