Welcome to the article The spring in a retractable ballpoint pen is 1 8 cm long with a spring constant of 340 N m When the pen is retracted. On this page, you will learn the essential and logical steps to better understand the topic being discussed. We hope the information provided helps you gain valuable insights and is easy to follow. Let’s begin the discussion!
Answer :
Final answer:
To extend the pen, the energy required is 0.00289 J.
Explanation:
To find the energy required to extend the pen, we can use the formula for the potential energy stored in a spring, which is given by: PE = 0.5 * k * x^2, where k is the spring constant and x is the displacement of the spring.
First, let's find the initial potential energy of the spring when it is compressed by 1.0 mm (0.001 m): PE1 = 0.5 * 340 N/m * (0.001 m)^2 = 0.00017 J.
Next, let's find the final potential energy of the spring when it is compressed by an additional 5.0 mm (0.005 m): PE2 = 0.5 * 340 N/m * (0.006 m)^2 = 0.00306 J.
The energy required to extend the pen is the difference between the final and initial potential energies:
ΔPE = PE2 - PE1 = 0.00306 J - 0.00017 J = 0.00289 J.
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Rewritten by : Brahmana