Welcome to the article If the volume of a carbon dioxide sample at 313 K is 686 6 mL what was its temperature when the volume was 437 3. On this page, you will learn the essential and logical steps to better understand the topic being discussed. We hope the information provided helps you gain valuable insights and is easy to follow. Let’s begin the discussion!
Answer :
Final answer:
The question can be solved using Charles's Law, which states that temperature and volume of a gas are directly proportional. Applying this law with given values, we find that the temperature of the carbon dioxide sample when its volume was 437.3 mL is 232 K.
Option A is correct.
Explanation:
The question, which is related to gas laws, can be solved using Charles's Law. Charles's Law states that the volume of a gas is directly proportional to its temperature, provided the pressure and the amount of gas remain constant. Therefore, the relationship between initial and final conditions of a gas can be represented as T1V1 = T2V2.
Here, T1 is the initial temperature (313K), V1 is the initial volume (686.6mL), T2 is the unknown final temperature we're solving for, and V2 is the final volume (437.3mL).
Solving Charles's Law equation, we get T2 = T1V2/V1 = (313K * 437.3mL) / 686.6mL = 232 K. So, the temperature of the carbon dioxide sample when its volume was 437.3 mL is 232 K. Therefore, the correct answer is a) 232 K.
Learn more about Charles's Law here:
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