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Welcome to the article Bao has two pencils a blue pen and a red pen in his pencil case Suppose he randomly withdraws one writing tool followed by another. On this page, you will learn the essential and logical steps to better understand the topic being discussed. We hope the information provided helps you gain valuable insights and is easy to follow. Let’s begin the discussion!

Bao has two pencils, a blue pen, and a red pen in his pencil case. Suppose he randomly withdraws one writing tool, followed by another, without replacing the first one.

a) What is the probability that Bao will randomly draw a red pen followed by a blue pen?

b) What is the probability that Bao will randomly draw a pen followed by a pencil?

Answer :

Final answer:

Thus, the probability of this event is (1/2) * (2/3) = 1/3.

Explanation:

The probability of Bao drawing a red pen followed by a blue pen can be found by calculating the probability of the first event multiplied by the conditional probability of the second event given that the first has occurred.

Bao has 4 items in total, so the probability of drawing a red pen on the first draw is 1/4. If the red pen is drawn, there are now 3 items remaining, making the probability of then drawing a blue pen 1/3. Therefore, the probability of this sequence is (1/4) * (1/3) = 1/12.

For Bao to draw a pen followed by a pencil, we must consider that there are 2 pens and 2 pencils in total. The probability of drawing a pen first is 2/4 (or 1/2), since there are 2 pens out of 4 items.

After drawing a pen, there will be 1 pen and 2 pencils left, so the probability of drawing a pencil next is 2/3.

Thus, the probability of this event is (1/2) * (2/3) = 1/3.

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Rewritten by : Brahmana