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A pen holder contains 12 identical pens, 6 of which do not write. A child randomly selects a pen, replaces it, and selects again. Find the probability that both pens do not write. (Enter your probability as a fraction.)

Answer :

Total pens = 12
Pens that do not write = 6
P(both pens that do not write) = (6/12)(6/12) = 1/4

Answer: The probability that both cannot write is 1/4

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Rewritten by : Brahmana

The probability that both pens do not write with replacement will be 1/4.

What is probability?

Its fundamental concept is that someone will nearly surely occur. The proportion of positive events in comparison to the total of occurrences.

Then the probability is given as,

P = (Favorable event) / (Total event)

A pen holder contains 12 indistinguishable pens, 6 of which don't compose. A kid haphazardly chooses a pen, replaces it, and chooses once more.

The probability that both pens do not write is given as,

P = (6/12) x (6/12)

P = (1/2) x (1/2)

P = 1 / 4

The probability that both pens do not write with replacement will be 1/4.

More about the probability link is given below.

https://brainly.com/question/795909

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