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A junk drawer at home contains five pens, two of which work. What is the probability that you randomly grab two pens from the drawer and don't end up with a pen that works?

Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.

Answer :

The probability that you randomly grab two pens from the drawer and don’t end up with a pen that works is [tex]\dfrac{4}{25}[/tex].

Given information:

The number of pens in the drawer is [tex]n=5[/tex].

The number of pens that doesn't work is [tex]a=2[/tex].

So, the number of pens which works will be, [tex]b=5-2=3[/tex].

The probability of grabbing a pen that doesn't work will be,

[tex]P_a=\dfrac{2}{5}[/tex]

Now, two pens are grabbed randomly from the drawer. So, the probability that you randomly grab two pens from the drawer and don’t end up with a pen that works will be calculated as,

[tex]P=(P_a)^2\\P=\dfrac{2}{5}\times \dfrac{2}{5}\\P=\dfrac{4}{5}[/tex]

Therefore, the value of the required probability will be [tex]\dfrac{4}{5}[/tex].

To know more about the random picking, refer to the link:

https://brainly.com/question/13448455

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Rewritten by : Brahmana

Answer:

The probability is [tex]P(k) = \frac{4}{25}[/tex]

Step-by-step explanation:

From the question we are told that

The number of pens from the drawer is n = 5

The number of pens that doesn't work is k = 2

The probability that a does not work is

[tex]p = \frac{k}{n}[/tex]

=> [tex]p = \frac{2}{5}[/tex]

The probability that a pen works is

[tex]q = 1- p[/tex]

[tex]q = 1- \frac{2}{5}[/tex]

=> [tex]q = \frac{3}{5}[/tex]

Generally the probability that ending up with a pen that doesn't work is mathematically represented as

[tex]P(k) = p^2[/tex]

=> [tex]P(k) = [\frac{2}{5} ]^2[/tex]

=> [tex]P(k) = \frac{4}{25}[/tex]