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Welcome to the article A gas canister can tolerate internal pressures up to 310 atmospheres If a 1 40 L canister holding 3 5 moles of gas is heated. On this page, you will learn the essential and logical steps to better understand the topic being discussed. We hope the information provided helps you gain valuable insights and is easy to follow. Let’s begin the discussion!

A gas canister can tolerate internal pressures up to 310 atmospheres. If a 1.40 L canister holding 3.5 moles of gas is heated to 1250°C, will the canister explode?

A. 313 atm and it will explode
B. 313 atm and it will not explode
C. 309 atm and it will explode
D. 309 atm and it will not explode

Answer :

Final answer:

After applying the Ideal Gas Law equation, we find that the calculated pressure exceeds the canister's limit of 310 atmospheres upon heating, thus it will likely explode.

Explanation:

The question pertains to the consequences of heating a gas in a closed container beyond its pressure limit. If we consider the Ideal Gas Law equation PV = nRT, where:

  • P designates pressure
  • V stands for volume
  • n signifies the amount of moles of gas
  • R represents the gas constant (which is 0.0821 L·atm/K·mol in this context)
  • T denotes temperature (in Kelvin)

We can rearrange this equation to calculate our desired pressure: P = nRT/V. Please remember to convert the temperature in the equation to Kelvin by adding 273.15 to the Celsius value, as the Kelvin scale is used in this law.

By substitifying the given values into the formula, we have P = (3.5 moles * 0.0821 L·atm/K·mol * (1250 + 273.15)K) / 1.40L. Upon calculation, the pressure turns out to overreach the canister's limit of 310 atmospheres, indicating that the canister will likely explode due to the high pressure generated.

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Rewritten by : Brahmana

The pressure of gas canister at 1250° Celsius is 312 atm which is more than the total internal pressure. Hence, it will explode.

Calculating the pressure of the volume of gas after being heated to 1250° Celsius. This will be done through ideal gas equation which is as follows -

PV = nRT, where P is pressure, V is volume, n is number of moles, R is gas constant and T is temperature.

Converting temperature to Kelvin

T = 1250 + 273

T = 1523 K

P = 3.5×0.082×1523/1.4

Performing multiplication on Right Hand Side of the equation

P = 437.1/1.4

Performing division on Right Hand Side of the equation

P = 312.2 atm

The gas canister will explode as the pressure exceeds.

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