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The volume changes from 1.25 L to 1.15 L at a temperature of 313 K. What is the final temperature?

Answer :

Answer: 288 K

Explanation:

Based on the information provided, this question is related to Charles's Law which describes how a volume of a gas is directly proportional to its absolute temperature at constant pressure. This relationship can be described through the following ratios:

V1/T1 = V2/T2

  • V1, represents the initial volume of the gas
  • T1, represents the initial temperature of the gas
  • V2, represents the final volume of the gas
  • T2, represents the final temperature of the gas

Since the question is asking for the final temperature of the gas after its initial volume (V1 = 1.25 L) changes to (V2 = 1.15 L) from an initial temperature of (T1 = 313 K), we need to rearrange the above ratios and solve for T2:

T2 = (V2 * T1)/V1 = (1.15 L * 313 K)/(1.25 L) = 287.96 (3 sig. figs.) = 288 K

This answer makes sense because if we consider the ideal gas law (PV=nRT), we see that if pressure (P) and the amount of the gas (n, in moles) remain constant, then the volume (V) is directly proportional to temperature (T). By decreasing the volume of the gas in this problem, we will also decrease the temperature.

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Rewritten by : Brahmana