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Answer :
The probability of choosing a black pen first and then another black pen from the bag, without replacement, is approximately 0.19.
To calculate the probability, we consider the number of favorable outcomes and divide it by the total number of possible outcomes. In this case, there are four black pens in the bag, and once the first black pen is chosen, there are three black pens left out of the total of eight pens remaining.
Therefore, the probability of selecting a black pen first is 4/8, and the probability of selecting another black pen second is 3/7. Multiplying these probabilities together, we get (4/8) * (3/7) = 12/56, which simplifies to approximately 0.19.
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