Welcome to the article If 19 5 tex text mol tex of an ideal gas is at 4 09 tex text atm tex and 313 tex text K tex. On this page, you will learn the essential and logical steps to better understand the topic being discussed. We hope the information provided helps you gain valuable insights and is easy to follow. Let’s begin the discussion!
Answer :
To find the volume of the gas, we can use the ideal gas law equation, which is given by:
PV = nRT
Where:
P = pressure (in atmospheres)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L•atm/mol•K)
T = temperature (in Kelvin)
In this case, we are given:
n = 19.5 mol
P = 4.09 atm
T = 313 K
Now, let's plug in these values into the equation:
(4.09 atm) * V = (19.5 mol) * (0.0821 L•atm/mol•K) * (313 K)
Now, we can solve for V by dividing both sides of the equation by 4.09 atm:
V = (19.5 mol) * (0.0821 L•atm/mol•K) * (313 K) / (4.09 atm)
Calculating this expression gives us the volume of the gas
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