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A sample of oxygen gas initially at 313 K was heated to 367 K. If the volume of the oxygen gas sample at 367 K is 742.0 mL, what was its volume at 313 K?

Answer :

Final answer:

To find the volume of the oxygen gas sample at 313 K, use Charles's Law

Explanation:

To solve this problem, we can use Charles's Law, which states that at constant pressure, the volume of a gas is directly proportional to its temperature.

We can use the formula:

V1/T1 = V2/T2

Where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.

Plugging the given values into the formula, we get:

V1/313 = 742/367

Cross multiplying and solving for V1, we find:

V1 = (742/367) * 313 = 632.70 mL

Therefore, the volume of the oxygen gas sample at 313 K would be 632.70 mL.

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Rewritten by : Brahmana