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Answer :
Final answer:
An sp3 atom typically cannot undergo resonance because it lacks a p orbital for electron delocalization. An exception exists when the sp3 atom has a lone pair adjacent to an sp² or sp atom, where it can rehybridize to sp² and then participate in resonance.
Explanation:
The answer is generally false. For resonance to occur, there must be at least two adjacent sp² or sp atoms since resonance involves the delocalization of electrons in p orbitals. An sp³ hybridized atom has its electrons localized in sp³ orbitals and does not have the necessary p orbital for delocalization to occur. An exception to this occurs when an sp³ atom has a lone pair and is adjacent to an sp²- or sp-hybridized atom.
In this specific case, the sp³ atom can rehybridize to sp², placing its lone pair in the vacant p orbital, and thus participate in resonance. For instance, the benzene molecule showcases resonance with each of its carbon atoms being sp² hybridized, allowing electron delocalization throughout the ring structure. However, an sp³ carbon without an adjacent sp² or sp carbon cannot partake in resonance.
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Rewritten by : Brahmana