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Answer :
The ear canal resonates best at a frequency that is determined by the length and shape of the canal. Typically, the ear canal is about 2.5 cm long and acts like a tube that is closed at one end and open at the other.
In physics, this type of tube resonates at specific frequencies called the fundamental frequency and its harmonics. The fundamental frequency (or first resonance) for a tube closed at one end can be calculated using the formula for the speed of sound and the length of the tube:
[tex]f = \frac{v}{4L},[/tex]
where:
- [tex]f[/tex] is the resonant frequency,
- [tex]v[/tex] is the speed of sound in air (approximately 343 meters per second at room temperature), and
- [tex]L[/tex] is the length of the ear canal in meters.
Given that the average human ear canal is about 2.5 cm (or 0.025 meters), we can substitute into the formula:
[tex]f = \frac{343}{4 \, \times \, 0.025} \approx 3430 \, \text{Hz}.[/tex]
Thus, the ear canal resonates best at approximately 3,430 Hz, enhancing our sensitivity to sounds around this frequency. This resonance helps us perceive speech sounds more clearly, as many consonant sounds fall within this frequency range.
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Rewritten by : Brahmana