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Answer :
The relevant harmonic frequencies of a 30 mm ear canal, modeled as a 1/4 length resonator, can be calculated using the formula for the resonant frequencies of a closed tube.
The answer to the question is that the relevant harmonic frequencies can be determined by dividing the speed of sound in air (approximately 343 m/s at room temperature) by four times the length of the ear canal (30 mm or 0.03 m in this case).
By applying the formula f = (c/4L), where f represents the frequency, c is the speed of sound, and L is the length of the ear canal, we can compute the harmonic frequencies.
Substituting the given values, we get f = (343 m/s) / (4 * 0.03 m) = 2858.33 Hz for the fundamental frequency (first harmonic).
To determine the higher harmonics, we multiply the fundamental frequency by integers. For example, the second harmonic would be 2 * 2858.33 Hz, the third harmonic would be 3 * 2858.33 Hz, and so on.
Therefore, the relevant harmonic frequencies of the 30 mm ear canal, modeled as a 1/4 length resonator, would be multiples of the fundamental frequency of 2858.33 Hz, determined by the length of the ear canal and the speed of sound in air.
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