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Welcome to the article At 313 K this reaction has a K c value of 0 0689 X g 2Y g rightleftharpoons 2Z g Calculate P at 313 K. On this page, you will learn the essential and logical steps to better understand the topic being discussed. We hope the information provided helps you gain valuable insights and is easy to follow. Let’s begin the discussion!

At 313 K, this reaction has a \( K_c \) value of 0.0689.

\[ X(g) + 2Y(g) \rightleftharpoons 2Z(g) \]

Calculate \( P \) at 313 K.

Answer :

Using the relationship between the equilibrium constant ('c') and pressure ('P'), we calculate that at 313K, the pressure of the reaction is approximately 14.512 atm.

To calculate P, or pressure, for this reaction at 313 K (Kelvin), we can use the equation for equilibrium constant (Kp) for gases, Kp = P^n where n is the change in moles of gas. In this reaction, the change between products and reactants is zero (2 - 2 = 0), so n is 0. Hence Kp = P^0 which gives Kp = 1. Therefore, 'c' should be the equilibrium constant at this temperature. The value of c given in the question is 0.0689. Thus P is calculated by P = 1/c, or 1/0.0689. The answer, rounded to three decimal places, is 14.512 atm.

Learn more about Equilibrium Constant here:

https://brainly.com/question/35152264

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Rewritten by : Brahmana