Welcome to the article A 63 g particle is moving to the left at 27 m s How much net work must be done on the particle to cause. On this page, you will learn the essential and logical steps to better understand the topic being discussed. We hope the information provided helps you gain valuable insights and is easy to follow. Let’s begin the discussion!
Answer :
Final answer:
A 63 g particle is moving to the left at 27 m/s, the net work must be done on the particle to cause it to move to the right at 34 m/s is C) 252 J to the right
Explanation:
To calculate the net work done on the particle, we need to find the change in its kinetic energy.
Kinetic energy is given by the formula KE = 1/2 * m * v²
where
m is the mass of the particle
v is its velocity.
Initially, the particle is moving to the left with a velocity of 27 m/s, so its initial kinetic energy is KE_initial = 1/2 * 63 g * (27 m/s)².
To cause the particle to move to the right with a velocity of 34 m/s, its final kinetic energy must be KE_final = 1/2 * 63 g * (34 m/s)².
The net work done on the particle is equal to the change in kinetic energy, which can be calculated as:
Net Work = KE_final - KE_initial = 1/2 * 63 g * (34 m/s)² - 1/2 * 63 g * (27 m/s)² = 252 J.
Therefore, the correct answer is C) 252 J to the right.
Thank you for reading the article A 63 g particle is moving to the left at 27 m s How much net work must be done on the particle to cause. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!
- What is the perimeter of the figure 32 0cm 51 0cm 19 0cm 63 0cm.
- The sign shows when a lift is safe to use the total mass of people should be 480 kg or less Fred and some other.
- The sign shows when a lift is safe to use the total mass of people should be 480 kg or less Fred and some other
Rewritten by : Brahmana